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Question

Two moles of a perfect gas undergo the following processes
(i) a reversible isobaric expansion from (1.0 am, 20.0L) to (1.0 atm, 40.0 L)
(ii) a reversible isochoric change of state from (1.0 atm, 40.0 L) to (0.5 atm, 40.0 L);
(iii) a reversible isothermal compression from (0.5 am, 40.0 L) to (1.0 atm, 20.0 L)
What is the total heat exchange here in Joules?

ln2=0.7, ln3=1.1, R=1/12 L atm/mol, 25/3 J/mol K, 1L atm=101 J

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Solution

Cyclic process:
For cyclic process change in state function must be zero thus
ΔE=0 for this cyclic process
ΔE=Q+W
Q=W=wi+wii+wiii (1)
work done in isobaric process
wi=PΔV=1×(4020)=20 Latm
work done in isochoric process and we know that for isochoric process dv=0
wii=pdv=0
work done in isothermal process:
pv=nRT=0.5×40 or 1×20=20 Latm
w=nRTlnvintialvfinal

wiii=20×ln4020Latm
on substituting in (1) we get
Q=606J

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