wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two moles of an ideal gas at 300K were cooled at constant volume so that the pressure is reduced to half the initial value. Then as a result of heating at constant pressure, the gas expands till it attains the original temperature. Find the total heat absorbed by the gas, if R is the gas constant.

A
150RJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
300RJ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
75RJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
100RJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 300RJ
In isochoric process PT
If pressure halves, temperature halves.
Heat released during isochoric process=nCV(T2T1)=2×(32R)(300150)J=450RJ
Heat absorbed during isobaric expansion=nCPR(T3T2)=2×(5R2)(300150)J=750RJ
Thus net heat absorbed=300RJ

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermodynamic Processes
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon