1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Compressibility Factor
Two moles of ...
Question
Two moles of an ideal gas expands spontaneously into vacuum, the work done is zero.
If true enter 1, else enter 0.
Open in App
Solution
In a vacuum,
P
e
x
t
=
0
since there is no external pressure acting on the gas.
Hence, work done=0
So, the given statement is correct.
Suggest Corrections
4
Similar questions
Q.
Two moles of an ideal gas expand spontaneously into vacuum. The work done is:
Q.
Three moles of an ideal gas expanded spontaneously into vacuum. The work done will be :
Q.
Work done in isobaric process is
P
Δ
V
. If true enter 1, else enter 0.
Q.
What will be the work done by
3
moles
of an ideal gas when it expands spontaneously in a vacuum?
Q.
C
P
−
C
V
for an ideal gas is equal to R. If true enter 1 else 0
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Equations Redefined
CHEMISTRY
Watch in App
Explore more
Compressibility Factor
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app