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Question

Two moles of an ideal gas initially at 270C and one atmospheric pressure are compressed isothermally and reversibly till the final pressure of the gas is 10 atm. Calculate q for the process.

A
11488 J
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B
11488 J
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C
12000 J
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D
12000 J
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Solution

The correct option is B 11488 J
work done in an isothermal reversible process is given as:

w=2.303nRT(logP1P2)
Here, n=2 mol
T=27+273=300 K
P1=1 atm, P2=10 atm
R=8.314 JK1mol1

w=2.303×2×8.314×300×log110
w=11488 J

For isothermal compression of ideal gas, U = 0 (as temperature is constant)

Further U=q+w
q=w=11488 J

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