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Question

# Two moles of an ideal monoatomic gas occupies a volume V at 27oC. The gas expands adiabatically to a volume 2V. Calculate (a) the final temperature of the gas and (b) change on its internal energy.

A
(a) 189K (b) 2.7 kJ
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B
(a) 195K (b) 2.7 kJ
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C
(a) 189K (b) 2.7kJ
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D
(a) 195k (b) 2.7kJ
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Solution

## The correct option is A (a) 189K (b) −2.7 kJIn an adiabatic process, PVγ=constantor TVγ−1=constantT2T1=(V1V2)γ−1For monoatomic gasγ=53T2=(300K)(V2V)53−1=189KChange in internal energy ΔU=nCvΔT =2(32)(253)(−111)=−2.7kJ

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