CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Two moles of helium gas undergo a cyclic process as shown in figure. Assuming the gas to be ideal, the net work done by the gas is:
945089_17735a3ae7734f2d86f832402703d297.PNG

A
200Rln2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
100Rln2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
300Rln2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
400Rln2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 200Rln2
Work done during process AB(AB) (Isobaric process)
WAB=nR(TBTA)
=100nR
Work done during process BC(BC) (Isothernal process)
WBC=nRTB ln(PnPc)
=nRTB ln(2)

Work done during process CD(CD)
WCD=nR(TCTD)
=100nR

Wnet=WAB+WDC+WCD+WDA

=nR 300 ln(12)+nR 400 ln(2)

=100 nR[3ln(12)+4 ln(2)]

=100 nR[ln(12)3×(2)4]

=100 nR ln(2)

Wnet=200 R ln(2) [n=2]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The First Law of Thermodynamics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon