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Question

Two moles of helium gas undergo a cyclic process as shown in figure. Assuming the gs to be ideal, calculate the following quantities in this process. The net change in the heat energy in J.
214615_ecf3ff75840e47bf81190ede82e5a8fe.png

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Solution

Since the process is cyclic, change in internal energy in one cycle is 0.
Hence net change in heat energy is equal to the negative of net work done.

WAB=P(VBVA)=2R(TBTA)

WBC=2RTBln(PBPC)=2R(400)ln(2)

WCD=P(VDVC)=2R(TDTC)=WAB

WDA=2RTDln(PDPA)=2R(300)ln(2)

Q=Wnet=2(8.314)ln(2)(400300)1153J

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