Question

Two moles of monoatomic gas $({\gamma }_1=\frac{5}{3})$ is mixed with three moles of diatomic gas$({\gamma }_2=\frac{7}{5})$ , then the value of $\gamma$ of the mixture is:

• A. $3$
• B. $2$
• C. $1.5$
• D. $1$

Answer 1

Answer: (C)

$1.5$

$N{\gamma }_{mix}=n_1{\gamma }_1+n_2{\gamma }_2$
${\gamma }_{mix}=\frac{n_1{\gamma }_1+n_2{\gamma }_2}{n_1+n_2}=\frac{2\left(\frac{5}{3}\right)+3\left(\frac{7}{5}\right)}{(2+3)}=1.506$