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Question

Two moles of N2 and two moles of H2 are taken in a closed vessel of 5 litres capacity and suitable conditions are provided for the reaction . When the equilibrium is reached it is found that a half mole of N2is used up. What is the equilibrium concentration of NH3?

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Solution

N2​​(g) +3H2(g) 2NH3(g)

Given Initially , amount of N2 = 2 moles
amount of H2 = 2 moles

When equillibrium is reached,
Amount of N2 used = 0.5 moles

Thus according to the balanced chemical reaction

1 mole of N2 on reaction will produce = 2 moles of NH3
Thus 0.5 mole ​of N2 on reaction will produce = 2 ×0.5 moles of NH3 = 1 mole of NH3

Thus at equillibrium 1 mol of NH3 will be present.

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