Question

Two moment of inertia of thin scale of length L and mass M about an axis passing through the centre of mass and perpendicular to length would be

• A. $\frac{M{L}^2}{12}$
• B. $\frac{M{L}^2}{4}$
• C. $\frac{M{L}^2}{3}$
• D. $M{L}^2$

Answer 1

The correct option is A $\frac{M{L}^2}{12}$

The momentum of inertia of a thin scale of length L and mass M about

an axis through the center of mass and perpendicular to length

$=\frac{M{L}^2}{12}$

Hence,

option $A$ is correct answer.