Two monatomic ideal gases $1$ and $2$ of molecular masses $m_{1}$ and $m_{2}$ respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas $1$ to that in gas $2$ is given by.

\sqrt{\frac{m_{1}}{m_{2}}}

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\sqrt{\frac{m_{2}}{m_{1}}}

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\frac{m_{1}}{m_{2}}

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\frac{m_{2}}{m_{1}}

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Solution

The correct option is B $\sqrt{\frac{m_{2}}{m_{1}}}$
$V_{r m} = \sqrt{\frac{r R T}{m}}$
i.e $v r \frac{1}{\sqrt{m}}$
which given $v - 1 \times \frac{1}{\sqrt{m_{1}}}$ and $v_{2} \times \frac{1}{\sqrt{m_{1}}}$
$\frac{v_{1}}{v_{2}} = \sqrt{\frac{m_{2}}{m_{1}}}$

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Two monatomic ideal gases 1 and 2 of molecular masses m1 and m2 respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas 1 to that in gas 2 is given by.

The correct option is B √m2m1Vrm=√rRTmi.e vr1√mwhich given v−1×1√m1 and v2×1√m1v1v2=√m2m1

Two monatomic ideal gases $1$ and $2$ of molecular masses $m_{1}$ and $m_{2}$ respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas $1$ to that in gas $2$ is given by.

The correct option is B $\sqrt{\frac{m_{2}}{m_{1}}}$
$V_{r m} = \sqrt{\frac{r R T}{m}}$
i.e $v r \frac{1}{\sqrt{m}}$
which given $v - 1 \times \frac{1}{\sqrt{m_{1}}}$ and $v_{2} \times \frac{1}{\sqrt{m_{1}}}$
$\frac{v_{1}}{v_{2}} = \sqrt{\frac{m_{2}}{m_{1}}}$