wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two monochromatic coherent point sources S1 and S2 are separated by a distance L. Each source emits light of wavelength λ, where L>>λ. The line S1S2 when extended meets a screen perpendicular to it at a point A.

A
The interference fringes on the screen are circular in shape
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
The interference fringes on the screen are straight lines perpendicular to the line S1S2A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Point A is an intensity maxima if L=nλ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Point A is always an intensity maxima for any separation L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A The interference fringes on the screen are circular in shape
This is a setup of fabry-perot interferometer. Due to axial symmetry around S1S2 line, the path difference along the plane containing A has circular symmetry. Thus the interference fringes form circular rings.
If point A is a maxima, path difference between the two rays is nλ=Distance between the two sources=L.

411020_164839_ans.png

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Intensity in YDSE
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon