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Question

Two monochromatic light waves of amplitudes A and 2A interfering at a point, have a phase differences of 60. The intensity of the resultant wave at that point will be proportional to

A
9A2
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B
3A2
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C
5A2
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D
7A2
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Solution

The correct option is D 7A2
The resultant amplitude is given by,

A2R=A21+A22+2A1A2cosϕ

A1,A2 Amplitudes of the interfering waves

ϕ - Phase difference between interfering waves

Resultant amplitude of the wave is given by

A2R=A2+(2A)2+[2×A×(2A)cos60]

A2R=A2(1+4+2)=7A2

We Know that, Intensity, I A2

IR A2R

IR 7A2

Hence, option (D) is correct.

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