Two motorcycles $M_{1}$ and $M_{2}$ are heading towards each other with a speed of $30 k m h^{- 1}$ each. A bird flies off $M_{1}$ at $60 k m h^{- 1}$ when distance between the motorcycles is $60 k m$ . It heads towards $M_{2}$ and then back to $M_{1}$ and so on. The total distance the bird moves till the motorcycles meet is

60 k m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

40 k m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 k m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 k m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $60 k m$
$v_{r e l} = 30 + 30 = 60 k m h^{- 1}$
Time in which motorcycles will meet
$= \frac{x}{v_{r e l}} = \frac{60 k m}{60 k m h^{- 1}} = 1 h$
Distance moved by the bird in 1 hr $= 60 \times 1 = 60 k m$

Suggest Corrections

Similar questions

Two trains ,each having a speed of 30km/h,are headed at each other on same track.A bird flies off one train to another with a constant speed of 60km/h when they are 60km apart till before they crash.the distance covered by the bird

A.20km

B.40km

C.60km

D.30km

Q. Two trains ,each having a speed of 30km/h ,r headed at each other on the same track. A bird that can fly 60km/h flies off the front of 1 train when they were 60km apart and heads directly to the other train . On reaching the
train ,the bird flies back to the first train.
What is the total distance the bird travels
before the train collide??

Q. Two trains each having a speed of

30 km/h

are headed at each other on the same straight track. A bird that can fly at

60 km/h

flies off from one train when they are

60 km

apart and heads directly for the other train. On reaching the other train, it flies directly back to the first and so forth. How many trips

(n)

can the bird make from one train to the other before the trains crash. Find the total distance that the bird travels assuming bird to be a point object.

Q. Two trains each having a speed of

30 kmph

are headed at each other on the same straight track. A bird that can fly at

60 kmph

flies off from one train when they are

60 km

apart and heads directly for the other train. On reaching the other train, it flies directly back to the first and so forth. How many trips can the bird make from one train to the other before the crash. Also find the total distance that the bird travels.

Q. Two cars start towards each other at the same time. One travels at 60 km/hr and another at 90 km/hr. A bird starts with one of the cars and flies at 400 km/hr towards the other one. When it gets to the other car, it turns and flies back towards the first and continues this to and fro flying when the cars are moving towards each other. How far does the bird travel before the cars pass each other? The distance between the cars is 3000 km.

Join BYJU'S Learning Program

Two motorcycles M1 and M2 are heading towards each other with a speed of 30kmh−1 each. A bird flies off M1 at 60kmh−1 when distance between the motorcycles is 60km. It heads towards M2 and then back to M1 and so on. The total distance the bird moves till the motorcycles meet is

The correct option is A 60kmvrel=30+30=60kmh−1Time in which motorcycles will meet=xvrel=60km60kmh−1=1hDistance moved by the bird in 1 hr=60×1=60km

The correct option is A $60 k m$
$v_{r e l} = 30 + 30 = 60 k m h^{- 1}$
Time in which motorcycles will meet
$= \frac{x}{v_{r e l}} = \frac{60 k m}{60 k m h^{- 1}} = 1 h$
Distance moved by the bird in 1 hr $= 60 \times 1 = 60 k m$