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Standard XII

Physics

Relative Velocity

Two motorcycl...

Question

Two motorcycles $M_{1}$ and $M_{2}$ are heading towards each other with a speed of $30 k m h^{- 1}$ each. A bird flies off $M_{1}$ at $60 k m h^{- 1}$ when distance between the motorcycles is $60 k m$ . It heads towards $M_{2}$ and then back to $M_{1}$ and so on. The total distance the bird moves till the motorcycles meet is

60 k m

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40 k m

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50 k m

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30 k m

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Solution

The correct option is A $60 k m$
$v_{r e l} = 30 + 30 = 60 k m h^{- 1}$
Time in which motorcycles will meet
$= \frac{x}{v_{r e l}} = \frac{60 k m}{60 k m h^{- 1}} = 1 h$
Distance moved by the bird in 1 hr $= 60 \times 1 = 60 k m$

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Two motorcycles M1 and M2 are heading towards each other with a speed of 30kmh−1 each. A bird flies off M1 at 60kmh−1 when distance between the motorcycles is 60km. It heads towards M2 and then back to M1 and so on. The total distance the bird moves till the motorcycles meet is

The correct option is A 60kmvrel=30+30=60kmh−1Time in which motorcycles will meet=xvrel=60km60kmh−1=1hDistance moved by the bird in 1 hr=60×1=60km

The correct option is A $60 k m$
$v_{r e l} = 30 + 30 = 60 k m h^{- 1}$
Time in which motorcycles will meet
$= \frac{x}{v_{r e l}} = \frac{60 k m}{60 k m h^{- 1}} = 1 h$
Distance moved by the bird in 1 hr $= 60 \times 1 = 60 k m$