Two moving coil meters- M1 and M2 have the following particulars- R1 - 10 - N1 - 30 A1 - 3-6 - 10-3 m2- B1 - 0-25 T R2 - 14 - N2 - 42 A2 - 1-8 - 10-3- B2 - 0-50 TThe spring constants are identical for the two meters-Determine the ratio of a current sensitivity and b voltage sensitivity of M2 and M1-

(a)Current sensitivity of M_1 is given as, I_s1=N_1B_1A_1/k_1 I_s2=N_2B_2A_2/k_2 where, #160;N=turns,B=Magnetic field,k=spring constant,A=areaR ...

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Two moving co...

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Two moving coil meters, $M_{1}$ and $M_{2}$ have the following particulars:
$R_{1} = 10 Ω, N_{1} = 30$
$A_{1} = 3.6 \times 10^{- 3} m^{2}, B_{1} = 0.25 T$
$R_{2} = 14 Ω, N_{2} = 42$
$A_{2} = 1.8 \times 10^{- 3}, B_{2} = 0.50 T$
(The spring constants are identical for the two meters).Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of $M_{2}$ and $M_{1}$ .

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R_{1} = 10 Ω, N_{1} = 30

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M_{2}, R_{2} = 14 Ω, N_{2} = 42,

A_{2} = 1.8 \times 10^{- 3} m^{2}, B_{2} = 0.5 T

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