Two moving coil meters, M₁ and M₂ have the following particulars:

R₁ = 10 Ω, N₁ = 30,

A₁ = 3.6 × 10^–3 m², B₁ = 0.25 T

R₂ = 14 Ω, N₂ = 42,

A₂ = 1.8 × 10^–3 m², B₂ = 0.50 T

(The spring constants are identical for the two meters).

Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M₂ and M₁.

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Solution

For moving coil meter M₁:

Resistance, R₁ = 10 Ω

Number of turns, N₁ = 30

Area of cross-section, A₁ = 3.6 × 10^–3 m²

Magnetic field strength, B₁ = 0.25 T

Spring constant K₁ = K

For moving coil meter M₂:

Resistance, R₂ = 14 Ω

Number of turns, N₂ = 42

Area of cross-section, A₂ = 1.8 × 10^–3 m²

Magnetic field strength, B₂ = 0.50 T

Spring constant, K₂ = K

(a) Current sensitivity of M₁ is given as:

And, current sensitivity of M₂is given as:

Ratio

Hence, the ratio of current sensitivity of M₂ to M₁ is 1.4.

(b) Voltage sensitivity for M₂ is given as:

And, voltage sensitivity for M₁is given as:

Ratio

Hence, the ratio of voltage sensitivity of M₂ to M₁ is 1.

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