Question

Two natural numbers differ by 6 and their sum is 36. Find the larger number

• A. 15
• B. 21
• C. 27
• D. 19

Answer 1

The correct option is B

21

Let larger number be x

Then smaller number will be = (x - 6).

Sum of the two numbers will be = x + (x -6)

Forming the equation:

x + (x -6) = 36

[rearranging the terms]

=x + x - 6 = 36

=2x - 6 = 36

=[adding 6 on both sides]

= 2x - 6 +6 = 36+6

= 2x = 42

[dividing both terms by 2]

$=\frac{2x}{2}=x=\frac{42}{2}=21$