Question

Two non-ideal batteries are connected in parallel. The equivalent EMF is smaller than either of the two EMFs?

• A. True
• B. False

Answer 1

The correct option is B False

Alright. Let’s try and find a scenario where the statement is violated.
Let’s take 2 cells of emf 1V and 2V, each having 1$\Omega$ internal resistance. Let’s find what the equivalent EMF is.
$E=\frac{E_1{R}_1+E_2{R}_2}{R_1+R_2}E=\frac{2+1}{2}E=1.5V$
Since E=1.5V is greater than one of the cell EMF’s, the given statement is false.
Always for such questions, remember that trial and error can help you prove it to be false.