Two non-negative integers are chosen at random from the set of non-negative integers with replacement. The probability that the sum of their squares is divisible by $10$ is

7 / 100

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6 / 50

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9 / 50

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12 / 50

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Solution

The correct option is A $7 / 100$

Hello student,
Please find the answer to your question below
Given Two non negative integers are chosen at random.
Let the 2 non negative integers be a,b then 0<=a,b<=9
Number of ways =10*10=100
The probability that their sum of their square is divisible by 10 is=(1,3),(2,6),(7,1),(4,8),(3,9),(2,4),(5,5) are 7
Probability=7/100

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Two non-negative integers are chosen at random from the set of non-negative integers with replacement. The probability that the sum of their squares is divisible by 10 is

Two non-negative integers are chosen at random from the set of non-negative integers with replacement. The probability that the sum of their squares is divisible by $10$ is