The correct option is B independent
Let the linear combination be
c1→v1+c2→v2=0
where c1 and c2 are scalars.
For linearly independency, sufficient condition to satisfy is
c1=c2=0
taking dot product with →v1
we get
→v1.(c1→v1+c2→v2)=→v1.0=0⇒c1→v1.→v1+c2→v1.→v2=0Since we know →v1.→v2=0⇒c1(→v1∣∣2=0since (→v1∣∣2 cannot be zeroSo c1=0Similary repeating same procedure forc2 we get c2=0So they will be linearly independent.