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Coulomb's Law - Mathematical Form

Two nucleons ...

Question

Two nucleons are at a separation of $1 f m$ . The net force between them is $F_{1}$ if both are neutrons, $F_{2}$ if both are protons, and $F_{3}$ if one is a proton and the other is a neutron then

A

F_{1} > F_{2} > F_{3}

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B

F_{3} = F_{1} > F_{2}

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C

F_{1} = F_{3} > F_{2}

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D

F_{1} = F_{2} > F_{3}

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Solution

The correct option is B $F_{3} = F_{1} > F_{2}$
Two nucleons are at separation $= 1 f_{m}$ . The net force between them $= F_{1}$ are neutrons $F_{2}$ is both are protons and $F_{3}$ if one is a proton and the other is a neutron then, nuclear forces are the strong forces of attraction which hold together the nucleons (neutrons and protons) in the tiny nucleus of an atom, in spite of strong electrostatic forces of repulsion between protons.
Nuclear forces act between a pair of neutrons, a pair of protons and also between a neutron, proton pair with the same strength.
This shows that nuclear forces are independent of charges. The attraction nuclear force is the same force any pair of nucleons.
Thus, $F_{1} = F_{3}$
When there are no electrostatic forces, but $F_{2} =$ Nuclear force $-$ repulsive electrostatic force.
Hence, $F_{3} = F_{1} > F_{2}$ .

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