Two number a, b are chosen from the set of integers $1, 2, 3, . . . . .39$ . The find the probability that the equation $7 a - 9 b = 0$ is satisfied.

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Solution

Given, $7 a - 9 b = 0 \Rightarrow b = \frac{7}{9} a$
Hence, number of pairs $(a, b)$ can be $(9, 7); (18, 14); (27, 21); (36, 28) .$
Hence,the required probability is $\frac{4}{^{39} C_{2}} = \frac{4}{741}$ .

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Two number a, b are chosen from the set of integers 1,2,3,.....39 . The find the probability that the equation 7a−9b=0 is satisfied.

Given,7a−9b=0⇒b=79aHence, number of pairs (a,b) can be (9,7);(18,14);(27,21);(36,28).Hence,the required probability is 439C2=4741.

Two number a, b are chosen from the set of integers $1, 2, 3, . . . . .39$ . The find the probability that the equation $7 a - 9 b = 0$ is satisfied.

Given, $7 a - 9 b = 0 \Rightarrow b = \frac{7}{9} a$
Hence, number of pairs $(a, b)$ can be $(9, 7); (18, 14); (27, 21); (36, 28) .$
Hence,the required probability is $\frac{4}{^{39} C_{2}} = \frac{4}{741}$ .