Two numbers a and b are chosen at random from the set of integers {1, 2, 3, ......, 15}. The probability that equation 2a – 3b = 0 is satisfied, is -
The possible set of numbers which satisfy the given condition 2a-3b=0
⇒ 2a = 3b
⇒ a = (3/2) b
Hence b has all the even number from the set A.
(3,2) (6,4)(9,6)(12,8)(15,10)
Now, chosen two random number from 15 = 15 C 2 = 105
Now, probability = favourable outcomes/ total sample space
= 5 / 105 = 1/21