Question

Two numbers are in the ratio 10:11. Their sum is 168. Find the numbers.

Answer 1

Let the two numbers be $10x$ and $11x$

Sum$=10x+11x=168$

$\Rightarrow 21x=168$

$\Rightarrow x=\frac{168}{21}=8$

$\therefore$ the numbers are $10\times 8=80$ and $11\times 8=88$

Hence the numbers are $80$ and $88$