Question

Two numbers are in the ratio 5:6 and if 4 is subtracted from each, they are reduced to 2:3, then the highest number is

• A. 8
• B. 4
• C. 12
• D. 10

Answer 1

The correct option is A

8

The highest number be 6y and the least number be 5y

$5y-\frac{4}{6y}-4=\frac{2}{3}$

On solving $y=\frac{4}{3}$

Highest number $=6\times \frac{4}{3}=8$