Question

Two numbers are in the ratio of $6:3$. If they differ by $18$, what are the numbers?

• A. $17,26$
• B. $42,76$
• C. $15,13$
• D. $36,18$

Answer 1

The correct option is D $36,18$

Let the two numbers be $6x$ and $3x$.

They are in the ratio of $6:3$.

By the given condition, we have

$6x-3x=18$

$\therefore 3x=18$

$\therefore x=6$

Therefore, the numbers would be $6x=6\times 6=36$ and $3x=3\times 6=18$.

So, the numbers are $36$ and $18$.