Two numbers are less than third number by 30% and 37% respectively. How much percent is the second number less than by the first?
10%
Let the third number is x.
Then the first number = (100-30)% of x
= 70% of x = 70x100
Similarly, second number is 63x100.
Difference = 70x100−63x100=7x100
So, required percentage is
⇒7x100×10070x×100% = 10%