Two numbers are successively drawn from the set $U = \{1, 2, 3, 4, 5, 6, 7, 8\}$ the second being drawn without replacing the first. The number of elementary events in the sample is:

$64$

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$56$

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$32$

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$14$

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Solution

The correct option is B
$56$

Explanation for the correct answer.
Find the number of events?
Given: $U = \{1, 2, 3, 4, 5, 6, 7, 8\}$
The number of ways of selecting the first number is ${}^{8}{C_{1} = 8}$
Remaining numbers are $7$
The number of ways of selecting the second number is ${}^{7}{C_{1}} = 7$
The number of elementary events is $= 8 \times 7 = 56$
Hence option (b) is correct.

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Two numbers are successively drawn from the set U=1,2,3,4,5,6,7,8 the second being drawn without replacing the first. The number of elementary events in the sample is:

Two numbers are successively drawn from the set $U = \{1, 2, 3, 4, 5, 6, 7, 8\}$ the second being drawn without replacing the first. The number of elementary events in the sample is: