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Question
Two numbers are there in a ratio 10:11. There sum is 168.find the numbers
Two numbers are there in a ratio 10:11. There sum is 168.find the numbers
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Solution
Let the common ratio be x
Numbers = 10x and 11x
So,
10x + 11x = 168
21x = 168
x = 168/21 = 8
Numbers are 10x = 10*8 = 80
and 11x = 11*8 = 88
Numbers = 10x and 11x
So,
10x + 11x = 168
21x = 168
x = 168/21 = 8
Numbers are 10x = 10*8 = 80
and 11x = 11*8 = 88
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