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Question

Two numbers both greater than 29, have HCF=29 and LCM=4147. The sum of the numbers is

A
666
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B
669
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C
696
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D
966
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Solution

The correct option is C 696
Product of numbers =29×4147
Let the numbers be 29a and 29b.
Then, 29a×29b=24×4147
ab=143
Now, co-primes with product 143 are (1,143),(11,13)
So the prime numbers are (29×1,29×143)and(29×11,29×13)
Since both numbers are greater than 29, the suitable pair is (29×11,29×13)
(319+377)=696.

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