Two numbers differ by 5, The sum of square of these numbers is 97. Find the product of the numbers.
24
66
14
36
x2+y2=97
(x−y)=5
square on both sides.
x2+y2−2xy=25
x2+y2−2xy=25.
We know that x2+y2=97.
Hence 97−2xy=25
⇒97−25=2xy
⇒72=2xy
⇒xy=722=36
Find the two natural numbers which differ by 5 and the sum of whose squares is 97.