Question

Two numbers 'p' and 'q' are selected without replacement in that order from the integers $1$ to $10$. What is the probability that $\frac{p}{q}$ is an integers?

• A. $1$
• B. $0.22$
• C. $0.1$
• D. $0.19$

Answer 1

The correct option is D $0.19$

Given,

Since the replacement is not allowed, the total number of cases are

$=10\times (10-1)=10\times 9=90$

The possible outcomes are $17$

$\to (2,1)(3,1)(4,1)(4,2)(5,1)(6,1)(6,2)(6,3)(7,1)(8,1)(8,2)(8,4)(9,1)(9,3)(10,1)(10,2)(10,5)$

The probability is $=\frac{17}{90}=0.19$