Two numbers X and Y are given by X - 2 -3-5 and Y - 2 -5-11- Then prime factorization of X - Y is

X = 2 ×3×5, which is a prime factorization of 30. Y = 2 ×5×11, which is a prime factorization of 110. Prime factorisation of X· Y=3300 is 2^2×3×5^2×11. ...

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Standard VI

Mathematics

Prime Factorisation

Two numbers X...

Question

Two numbers $X$ and $Y$ are given by $X = 2 \times 3 \times 5$ and $Y = 2 \times 5 \times 11.$ Then prime factorization of $X \cdot Y$ is

2 \times 3 \times 5 \times 11

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2 \times 3^{2} \times 5^{2} \times 11

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2 \times 3 \times 5^{2} \times 11^{2}

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2^{2} \times 3 \times 5^{2} \times 11

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Solution

The correct option is D $2^{2} \times 3 \times 5^{2} \times 11$
$X = 2 \times 3 \times 5$ , which is a prime factorization of 30.
$Y = 2 \times 5 \times 11$ , which is a prime factorization of 110.
Prime factorisation of $X \cdot Y = 3300$ is $2^{2} \times 3 \times 5^{2} \times 11$ .

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Two numbers X and Y are given by X=2×3×5 and Y=2×5×11. Then prime factorization of X⋅Y is

The correct option is D 22×3×52×11X=2×3×5, which is a prime factorization of 30. Y=2×5×11, which is a prime factorization of 110. Prime factorisation of X⋅Y=3300 is 22×3×52×11.

Two numbers $X$ and $Y$ are given by $X = 2 \times 3 \times 5$ and $Y = 2 \times 5 \times 11.$ Then prime factorization of $X \cdot Y$ is

The correct option is D $2^{2} \times 3 \times 5^{2} \times 11$
$X = 2 \times 3 \times 5$ , which is a prime factorization of 30.
$Y = 2 \times 5 \times 11$ , which is a prime factorization of 110.
Prime factorisation of $X \cdot Y = 3300$ is $2^{2} \times 3 \times 5^{2} \times 11$ .