Question

Two object are thrown with same velocity but are thrown at angle of ${25}^o$ and other at ${65}^o$, what will be the ratio of their ranges.

Answer 1

Given,

${\theta }_1={25}^0$

${\theta }_2={65}^0$

The horizontal range in the projectile motion is given by

$R=\frac{u^{2}sin2\theta }{g}$

$R\propto sin2\theta$

Ratio, $\frac{R_1}{R_2}=\frac{sin(2\times {25}^0)}{sin(2\times {65}^0)}$

$\frac{R_1}{R_2}=1.28$