Two objects A and B of mass 6 kg and 1.5 kg respectively are kept at two different heights h and 2h. What will be the relation in the potential energy of the blocks?

P E_{A}

2 P E_{B}

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P E_{A}

4 P E_{B}

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4 P E_{A}

P E_{B}

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2 P E_{A}

P E_{B}

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Solution

The correct option is A $P E_{A}$ = $2 P E_{B}$
Potential energy is the energy possessed by a body by virtue of its position.
It is calculated as mgh, where h is the height of the object above the ground.

Given:
Mass of object A, $m_{A}$ = 6 kg
Mass of object B, $m_{B}$ = 1.5 kg
Height of object A, $h_{A}$ = h
Height of object B, $h_{B}$ = 2h
PE of object A = $P E_{A}$ = 6 × g × h = 6gh
PE of object B = $P E_{B}$ = 1.5 × g × 2h = 3gh
⇒ $P E_{A}$ = $2 P E_{B}$

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