The correct option is B Object B
Qualitative approach:
The percentage of an object submerged in the water will increase with its absolute density. Since more fraction of B is immersed, it has more density than A.
Mathematical approach:
Assume:
Density of water: ρw,
Density of A: ρA,
Density of B: ρB,
Volume of A (equal to the volume of B): V
According to the Archimedes' principle, weight of displaced water by an object is equal to the buoyant force or upthrust on that object.
If body is floating the weight of object is also equal to the buoyant force.
For A,
ρw×V3=ρAV
ρA=ρw3 -------(1)
For B,
ρw×V2=ρBV
ρB=ρw2 -------(2)
⟹ρAρB=23
Hence, object B has comparatively higher density value than A.