Question

Two objects are one side of a Tower. Their angles of depression from the top of the Tower are ${45}^{\circ }$ and ${60}^{\circ }$ respectively. If the distance between two objects will be-

• A. $6.34$ metre
• B. $63.4$ metre
• C. $63$ metre
• D. $64$ metre

Answer 1

Answer: (B)

$63.4$ metre

In $\Delta ABC$
$\tan {45}^{\circ }=\frac{AB}{BD}$
$1=\frac{150}{BD}$
$BD=150m$
In $\Delta ABC$ ,
$\tan {60}^{\circ }=\frac{AB}{BC}$
$\sqrt{3}=\frac{150}{BC}$
$BC=50\sqrt{3}=86.60m$
Hence, the distance between two objects CD will be
$=150-86.60$
=63.4 metre