Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is $2.5 m s^{- 1}$ before the collision during which they stick together. What will be the velocity of the combined object after the collision?

$0 m s^{- 1}$

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$2 m s^{- 1}$

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1 m s^{- 1}

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$3 m s^{- 1}$

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Solution

The correct option is A
$0 m s^{- 1}$

Mass of each object $m_{1} = m_{2} = 1.5 k g$

Initial velocity of first object, $v_{1} = 2.5 m s^{- 1}$

Initial velocity of second object, $v_{2} = 2.5 m s^{- 1}$ (since direction is opposite)

Combined mass after collision $= m_{1} + m_{2}$

= 1.5 + 1.5 kg = 3.0 kg

From the principle of conservation of momentum,

$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2}) v$

$1.5 \times 2.5 + 1.5 \times (- 2.5) = (3.0) v$

0 = 3.0 v

$v = 0 m s^{- 1}$

That is combined object comes to rest after the collision.

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Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 ms−1 before the collision during which they stick together. What will be the velocity of the combined object after the collision?

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