Two objects, each of mass $1.5 k g$ are moving in the same straight line but in opposite directions. The velocity of each object is $2.5 {m s}^{- 1}$ before the collision during which they stick together. What will be the velocity of the combined object after the collision?

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Solution

by conservation of momentum
$1.5 \times 2.5 - 1.5 \times 2.5 = 2 \times 1.5 \times v$
combined velocity v=o

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Two objects, each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5ms−1 before the collision during which they stick together. What will be the velocity of the combined object after the collision?

by conservation of momentum1.5×2.5−1.5×2.5=2×1.5×vcombined velocity v=o

Two objects, each of mass $1.5 k g$ are moving in the same straight line but in opposite directions. The velocity of each object is $2.5 {m s}^{- 1}$ before the collision during which they stick together. What will be the velocity of the combined object after the collision?

by conservation of momentum
$1.5 \times 2.5 - 1.5 \times 2.5 = 2 \times 1.5 \times v$
combined velocity v=o