wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5ms1 before the collision during which they stick together. What will be the velocity of the combined object after collision?

A
0 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3.75 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.75 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 0 m/s
Let the objects be A and B moving from opposite directions in the same straight line.
Initial momentum of A =m×v
=1.5×2.5=3.75kgms1
Also, initial momentum of B
=m×v=1.5×(2.5)=3.75kgms1
If v is the velocity of the objects after collision, then final momentum after collision =3×v
Using the law of conservation of momentum, final momentum of A and B =
initial momentum of A + initial momentum of B
or 3×v=3.753.75
or 3×v=0 or v=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservation of Momentum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon