Two objects each of mass $2 k g$ all moving in the same straight line but in opposite directions. The velocity of each object is $2.5 m / s$ before the collision during which they stick together. What will the velocity of the combine object be after collision.

2 m / s

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6 m / s

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0 (z e r o)

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6.8 m / s

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Solution

The correct option is C $0 (z e r o)$
Initial momentum of object 1 = mv
$= 2 \times 2.5 = 5 k g m / s$
Initial momentum of object -2 = mx (-v)
$= 2 \times (- 2.5)$
$= - 5 k g m / s$
Momentum of the combination of two after collision $= 5 + (- 5) = 0$
So, velocity of combination $= \frac{Momentum of combination}{Mass of combination}$
$= \frac{0}{4} = 0$

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Two objects each of mass 2kg all moving in the same straight line but in opposite directions. The velocity of each object is 2.5m/s before the collision during which they stick together. What will the velocity of the combine object be after collision.

The correct option is C 0(zero)Initial momentum of object 1 = mv=2×2.5=5kgm/sInitial momentum of object -2 = mx (-v)=2×(−2.5)=−5kgm/sMomentum of the combination of two after collision =5+(−5)=0So, velocity of combination =Momentum of combinationMass of combination=04=0

Two objects each of mass $2 k g$ all moving in the same straight line but in opposite directions. The velocity of each object is $2.5 m / s$ before the collision during which they stick together. What will the velocity of the combine object be after collision.