Let the masses of the two bodies be (m1) = m kg and (m2) = m kg.
Velocity of the first body, (v1) = 2 m/s
Velocity of the first body, (v2) = 6 m/s
The required ratio is-
= (Kinetic energy)1(Kinetic energy)2=12(m1)(v1)212(m2)(v2)2
=m(2)2m(6)2=19
The ratio of the kinetic energies is, (Kinetic energy)1(Kinetic energy)2=1:9.