Question

Two objects move towards each other till they meet at a point. The speed of first object is $5m{s}^{-1}$ and the speed of the second object is $10m{s}^{-1}$. If the distance between the objects is $30m$ initially, what is the difference between the distances travelled by the two bodies?

• A. $5m$
• B. $10m$
• C. $20m$
• D. $30m$

Answer 1

The correct option is B $10m$

Given, speed of first body = $5m{s}^{-1}$.
Speed of second body = $10m{s}^{-1}$.
Let the time taken for the two bodies to meet be 't'.
Distance travelled by the first body = $5\times t$.
Distance travelled by the second body = $10\times t$.
Since the total of the distances travelled = 30 m,
$5t+10t=30$
$\Rightarrow 15t=30$
$\Rightarrow t=2s$.
Distance travelled by the first body = $5\times 2=10m$.
Distance travelled by the second body = $10\times 2=20m$.
Difference in distances = $20-10=10m$.