Two objects moving along the same straight line are leaving point A with an acceleration a, 2a & velocity 2u, u respectively at time t=0. The distance moved by the object with respect to point A when one object overtakes the other is
A
6u2a
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2u2a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4u2a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
noneofthese
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A6u2a Let both will meet at point B x=2ut+1/2at2 x=ut+12(2a)t2 So 2ut+12at2=ut+at2 ut=12at2⇒t=2ua So x=2u(2ua)+12a(2ua)2=6u2a