Two objects of equal masses have the velocities $2 m / s$ and $3 m / s$ respectively. Find out the ratio of their kinetic energies respectively.

1 : 2

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1 : 4

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4 : 9

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9 : 4

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Solution

The correct option is C $4 : 9$
Given,
The mass of the two bodies is same.
$v_{1} = 2 m / s$
$v_{2} = 3 m / s$
we know that Kinetic energy (KE) = $\frac{1}{2} m v^{2}$
Ratio of kinetic energies = $\frac{m {v_{1}}^{2}}{m {v_{2}}^{2}}$

Ratio of kinetic energy = $(\frac{2}{3})^{2} = \frac{4}{9}$ .

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1 \times 10^{- 3} kg

4 \times 10^{- 3} kg

^{'} m^{'}

^{'} 4 m^{'}

2 : 1

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4

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