Two open pipes of length 25 cm and 25.5 cm produced 10 beat/second. The velocity of sound will be:

255 m/s

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250 m/s

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350 m/s

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None of these

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Solution

The correct option is A 255 m/s
Given,

$l_{1} = 25 c m$

$l_{2} = 25.5 c m$

$n_{1} - n_{2} = 10 b e a t / s e c$

$n_{1} - n_{2} = \frac{v}{2 l_{1}} - \frac{v}{2 l_{2}}$

$\frac{v}{2} (\frac{1}{l_{1}} - \frac{1}{l_{2}}) = 0.1$

$v = 255 m / s$

The correct option is A.

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