Question

Two opposite angles of a parallelogram are $(3x-2{)}^0$ and $(50-x{)}^0$. Find $x$

Answer 1

We know that opposite angles of a parallelogram are equal. Therefore,

given $2$ angles are of equal magnitude.

$3x-2=50-x$

$3x+x=50+2$

$4x=52$

$x=13$

Therefore the angles are;

$50-x=>50-13={37}^0$

$3x-2=>3\left(13\right)-2=39-2={37}^0$

The other $2$ angles of parallelogram are

$180-37={143}^0$

Therefore all angles of parallelogram are;

${37}^0,{143}^0,{37}^0,{143}^0$