Two opposite charge particles under mutual force of attraction are given uniform initial velocity of same magnitude in opposite direction. They lose $220 J$ of their $K . E$ after travelling $2 m$ distance. Calculate the work done by internal force

Zero

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- 220 J

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+ 220 J

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110 J

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Solution

The correct option is B $- 220 J$

Since they are under force of attraction and displacement is given in opposite direction (They are made to separate).
Therefore work done will be $- v e$ and its magnitude will be the change in kinetic energy.

$∴$ Work done by internal force $=$ change in the $K . E$
$W = - 220 J$ ,
Here we get $- v e$ the direction of force of attraction is opposite to the direction of displacement.

Hence option B is the correct answer

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Two opposite charge particles under mutual force of attraction are given uniform initial velocity of same magnitude in opposite direction. They lose 220 J of their K.E after travelling 2 m distance. Calculate the work done by internal force

Two opposite charge particles under mutual force of attraction are given uniform initial velocity of same magnitude in opposite direction. They lose $220 J$ of their $K . E$ after travelling $2 m$ distance. Calculate the work done by internal force