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Question
Two optically flat plates of glass are kept at a small angle \(\theta\) as shown in the figure. Monochromatic light is incident vertically.
If the wavelength of light used to get a fringe spacing of 1 mm is 450 nm, the wavelength of light (in mm) to get a fringe spacing of 1.5 mm is
If the wavelength of light used to get a fringe spacing of 1 mm is 450 nm, the wavelength of light (in mm) to get a fringe spacing of 1.5 mm is
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Solution
$\text{Given data : 1 mm = 450 mm, Spacing =1.5 mm}$
$\text{\(n=\dfrac{2}{450}\) As given in question }$
\(1.5=n\times\dfrac{\lambda_{2}}{2}\)
\(\lambda_{2}=\dfrac{1.5\times2}{n}=\dfrac{1.5\times 2}{\dfrac{2}{450}}=1.5\times 450=675\, mm\)
$\text{\(n=\dfrac{2}{450}\) As given in question }$
\(1.5=n\times\dfrac{\lambda_{2}}{2}\)
\(\lambda_{2}=\dfrac{1.5\times2}{n}=\dfrac{1.5\times 2}{\dfrac{2}{450}}=1.5\times 450=675\, mm\)
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