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Standard XII

Chemistry

Nucleophilic Substitution in Alkyl Halides

Two organic c...

Question

Two organic compounds $A$ and $B$ have $s p^{2}$ hybridized carbon atoms. $A$ can decolourise alkaline $K M n O_{4}$ while $B$ cannot $A$ and $B$ could be:

ethylene, acetylene

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propylene, acetylene

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benzene, acetylene

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ethylene, benzene

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Solution

The correct option is D ethylene, benzene
Ethylene ( $C_{2} H_{4}$ ) reacts with $K M n O_{4}$ and decolourises pink colour of Baeyer reagent.

But, benzene $C_{6} H_{6}$ does not get oxidized with Baeyer reagent due to extensive delocalization of pi-electrons of benzene. (aromatic stable)

Option D is correct.

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Two organic compounds A and B have sp2 hybridized carbon atoms. A can decolourise alkaline KMnO4 while B cannot A and B could be:

The correct option is D ethylene, benzeneEthylene (C2H4) reacts with KMnO4 and decolourises pink colour of Baeyer reagent. But, benzene C6H6 does not get oxidized with Baeyer reagent due to extensive delocalization of pi-electrons of benzene. (aromatic stable)Option D is correct.

Two organic compounds $A$ and $B$ have $s p^{2}$ hybridized carbon atoms. $A$ can decolourise alkaline $K M n O_{4}$ while $B$ cannot $A$ and $B$ could be: